Question

a rectangular high jump pit is 25 feet long and 10 feet wide. which of these is closest to the diagonal distance across the pit? 26 feet 27 feet 28 feet 25 feet

Explanation:

Step1: Apply Pythagorean theorem

In a rectangle, if length \(l = 25\) feet and width \(w=10\) feet, and diagonal \(d\) is the hypotenuse of a right - triangle. By the Pythagorean theorem \(d^{2}=l^{2}+w^{2}\). So \(d^{2}=25^{2}+10^{2}\).

Step2: Calculate \(l^{2}+w^{2}\)

\(25^{2}=625\) and \(10^{2} = 100\), then \(d^{2}=625 + 100=725\).

Step3: Find \(d\)

\(d=\sqrt{725}\). Since \(26^{2}=676\), \(27^{2}=729\), \(28^{2}=784\) and \(25^{2}=625\). \(\sqrt{725}\approx26.92\)

Answer:

27 feet