Question

a rectangle’s length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w?
○ 2w(2w + 5) = 50
○ 2w(w + 5) = 50
○ w(2w + 5) = 50
○ w(w + 5) = 50

Explanation:

Step1: Define length in terms of width

Let width be \( w \). Length is 5 more than twice width, so length \( l = 2w + 5 \).

Step2: Recall area formula for rectangle

Area of rectangle is \( A = l \times w \). Substitute \( l = 2w + 5 \) and \( A = 50 \).
We get \( w(2w + 5) = 50 \).

Answer:

C. \( w(2w + 5) = 50 \) (assuming the third option is labeled C; if original labels differ, adjust to match, e.g., if third option is C, then C. \( w(2w + 5) = 50 \))