QUESTION IMAGE
Question
read the proof.
given: \\(\overline{ae} \perp \overline{ec}; \overline{bd} \perp \overline{dc}\\)
prove: \\(\triangle aec \sim \triangle bdc\\)
image of a geometric figure with points a, e, d, c, b
| statement | reason |
|---|---|
| 2. \\(\angle aec\\) is a rt. \\(\angle\\); \\(\angle bdc\\) is a rt. \\(\angle\\) | 2. definition of perpendicular |
| 3. \\(\angle aec \cong \angle bdc\\) | 3. all right angles are congruent |
| 4.? | 4. reflexive property |
| 5. \\(\triangle aec \sim \triangle bdc\\) | 5. aa similarity theorem |
what is the missing statement in step 4?
\\(\circ\\) \\(\angle ace \cong \angle bcd\\)
\\(\circ\\) \\(\angle eab \cong \angle dbc\\)
\\(\circ\\) \\(\angle eac \cong \angle eac\\)
\\(\circ\\) \\(\angle cbd \cong \angle dbc\\)
Step1: Identify shared angle
The angle at point C is common to both triangles.
Step2: Apply reflexive property
A common angle is congruent to itself by reflexive property.
Step3: Match with AA similarity
Step 3 has right angles congruent; step4 needs another congruent angle for AA.
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∠ACE ≅ ∠BCD