Question

1 rated sturd - i - floor
2 24 oc 23/32 inch
3 sized for spacing
4 t&g net width 47 - 1/2
exposure 1
5 ps 1 - 07 underlayment
prp - 108
6
7
8
figure 3 - 11 sample of a grade stamp.
number 6 is the panel thickness that is 1/32\ smaller than thick.
1/2\
3/4\
7/8\
5/8\

Explanation:

Step1: Set up the equation

Let the unknown thickness be \(x\). We know that \(x-\frac{1}{32}=\frac{23}{32}\).

Step2: Solve for \(x\)

Add \(\frac{1}{32}\) to both sides of the equation: \(x=\frac{23}{32}+\frac{1}{32}\).
Using the rule for adding fractions with the same denominator \(\frac{a}{c}+\frac{b}{c}=\frac{a + b}{c}\), we have \(x=\frac{23 + 1}{32}=\frac{24}{32}\).
Simplify \(\frac{24}{32}\) by dividing numerator and denominator by 8, getting \(x=\frac{3}{4}\).

Answer:

\(\frac{3}{4}\)