rate of volume change (ml/hr)
\\text{rate of volume change}(\frac{\text{ml}}{\text{hr}}) = \frac{\text{final volume}(\text{ml}) - \text{initial volume}(\text{ml})}{\text{time}(\text{min})} \times 60(\frac{\text{min}}{\text{hr}})\

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{ "quality": "clear", "question_count": 2, "skills_matched": [ "step_cot", "table_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Rate of Photosynthesis Calculation", "Volumetric Photosynthesis Measurement" ], "new_concepts": [], "current_concepts": [ "Rate of Photosynthesis Calculation", "Volumetric Photosynthesis Measurement" ] } ## Calculate Tube 1 rate Using the *Rate of Photosynthesis Calculation* and *Volumetric Photosynthesis Measurement* knowledge points $$ \begin{aligned} \text{Initial Volume} &= 3\text{ mL}\ \text{Final Volume} &= 6.8\text{ mL}\ \text{Time} &= 20\text{ min}\ \text{Rate} &= \frac{6.8 - 3}{20} \times 60 = \frac{3.8}{20} \times 60 = 3.8 \times 3 = 11.4\text{ mL/hr} \end{aligned} $$ ## Calculate Tube 2 rate Using the *Rate of Photosynthesis Calculation* and *Volumetric Photosynthesis Measurement* knowledge points $$ \begin{aligned} \text{Initial Volume} &= 3\text{ mL}\ \text{Final Volume} &= 2.1\text{ mL}\ \text{Time} &= 20\text{ min}\ \text{Rate} &= \frac{2.1 - 3}{20} \times 60 = \frac{-0.9}{20} \times 60 = -0.9 \times 3 = -2.7\text{ mL/hr} \end{aligned} $$ | Tube | Rate of volume change ($\text{mL/hr}$) | |---|---| | Tube 1 (White Light) | $11.4$ | | Tube 2 (Covered) | $-2.7$ | { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Biology", "Photosynthesis Experiments" ] }

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Calculate Tube 1 rate

Calculate Tube 2 rate

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