Question

quiz instructions
you can complete this review up to 3 times. it will be worth 2.5 points extra credit onto the exam.
question 8 1 pts
a hockey puck slides at a constant velocity across a frictionless ice rink. the ice exerts a normal force on the puck equal to 5.3 newtons. what must be the weight of the puck?

Explanation:

Step1: Analyze Forces on Puck

The hockey puck moves on a horizontal, frictionless ice rink at constant velocity. In vertical direction, forces are normal force (\(F_N\)) upward and weight (\(W\)) downward. Since velocity is constant, acceleration is zero, so net force in vertical direction is zero. Thus, \(F_N\) and \(W\) are balanced.

Step2: Relate Normal Force and Weight

For an object on a horizontal surface, normal force equals weight when there's no vertical acceleration. Given \(F_N = 5.3\space N\), so weight \(W = F_N = 5.3\space N\).

Answer:

\(5.3\space N\)