Question

quiz: combining rational e
hs: algebra 2b m (sequential) / 4:

1. simplify.

\\(\frac{3}{8x^3y^3} - \frac{1}{4xy}\\)
\\(\frac{3 - 2x^2y^2}{8x^3y^3}\\)
\\(\frac{x^2y^2 - 3}{4x^3y^3}\\)
\\(\frac{2x^2y^2 - 3}{8x^3y^3}\\)
\\(\frac{2}{8x^3y^3}\\)

Explanation:

Step1: Find common denominator

Common denominator is $8x^3y^3$.

Step2: Rewrite second term

$\frac{1}{4xy} = \frac{2x^2y^2}{8x^3y^3}$

Step3: Subtract fractions

$\frac{3}{8x^3y^3} - \frac{2x^2y^2}{8x^3y^3} = \frac{3 - 2x^2y^2}{8x^3y^3}$

Answer:

$\frac{3 - 2x^2y^2}{8x^3y^3}$