Question

for questions 17 $f(x) = x^2 + 4x + 1$ and $g(x) = x^2 + 2x - 4$

1. find $f(g(- 3))$

Explanation:

Step1: Calculate \( g(-3) \)

Substitute \( x = -3 \) into \( g(x) = x^2 + 2x - 4 \):
\( g(-3) = (-3)^2 + 2(-3) - 4 = 9 - 6 - 4 = -1 \)

Step2: Calculate \( f(g(-3)) = f(-1) \)

Substitute \( x = -1 \) into \( f(x) = x^2 + 4x + 1 \):
\( f(-1) = (-1)^2 + 4(-1) + 1 = 1 - 4 + 1 = -2 \)

Answer:

\(-2\)