Question

question
what is the volume of a cylinder with a height of 9.2 ft and a base with a radius of 3.9 ft, to the nearest tenth of a cubic foot?
answer attempt 1 out of 2
ft³ submit answer

Explanation:

Step1: Recall the formula for the volume of a cylinder

The volume \( V \) of a cylinder is given by the formula \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Substitute the given values into the formula

We are given that \( r = 3.9\space\text{ft} \) and \( h=9.2\space\text{ft} \). Substituting these values into the formula, we get \( V=\pi\times(3.9)^{2}\times9.2 \).
First, calculate \( (3.9)^{2} \): \( 3.9\times3.9 = 15.21 \).
Then, multiply this result by \( 9.2 \): \( 15.21\times9.2=140.012 \).
Now, multiply by \( \pi \): \( V=\pi\times140.012\approx3.14159\times140.012 \).
Calculating this, we have \( 3.14159\times140.012\approx439.7 \) (rounded to the nearest tenth).

Answer:

\( 439.7 \)