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Question
question if $f(x) = x^6 - 4x - 4$, then what is the remainder when $f(x)$ is divided by $x - 1$?
Step1: Recall the Remainder Theorem
The Remainder Theorem states that if a polynomial \( f(x) \) is divided by \( x - a \), the remainder is \( f(a) \). Here, we are dividing \( f(x) \) by \( x - 1 \), so \( a = 1 \).
Step2: Evaluate \( f(1) \)
Given \( f(x)=x^{6}-4x - 4 \), substitute \( x = 1 \) into the polynomial:
$$
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The remainder is \(-7\).