Question

question 5 of 5 type the correct answer in the box. use numerals instead of words. what is dc to the nearest tenth? dc = \boxed{}

Explanation:

Step1: Find BC using Pythagoras

In right triangle \(ABC\), \(AB = 15\), \(AC = 22\). By Pythagoras, \(BC=\sqrt{AC^{2}-AB^{2}}=\sqrt{22^{2}-15^{2}}=\sqrt{484 - 225}=\sqrt{259}\approx16.1\)

Step2: Find DC using Pythagoras

In right triangle \(DBC\), \(DB = 28\), \(BC\approx16.1\). By Pythagoras, \(DC=\sqrt{DB^{2}+BC^{2}}=\sqrt{28^{2}+16.1^{2}}=\sqrt{784+259.21}=\sqrt{1043.21}\approx32.3\)

Answer:

32.3