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triangle jkl is similar to triangle mno. find om. round your answer to the nearest tenth if necessary. figures are not drawn to scale.
answer attempt 1 out of 2
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Step1: Set up the proportion
Since \(\triangle{JKL}\sim\triangle{MNO}\), the ratios of corresponding sides are equal. So, \(\frac{OM}{JL}=\frac{NO}{KL}\).
Step2: Substitute the values
We know \(JL = 25\), \(KL=18\), and \(NO = 5\). Let \(OM=x\). Then the proportion becomes \(\frac{x}{25}=\frac{5}{18}\).
Step3: Solve for \(x\)
Cross - multiply: \(18x=25\times5\). So, \(18x = 125\). Then \(x=\frac{125}{18}\approx6.9\).
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\(6.9\)