Question

question 1. a student pushes an 8 kg box with a force of 28 n across the floor. the friction between the box and the floor is 6 n. what is the acceleration of the box? a. 0.36 m/s² b. 2.75 m/s² c. 3.5 m/s² d. 0.75 m/s²

Explanation:

Step1: Find Net Force

The applied force is 28 N, friction is 6 N (opposing). Net force \( F_{net} = 28 - 6 = 22 \, \text{N} \).

Step2: Apply Newton's Second Law

Newton's second law: \( F = ma \), so \( a = \frac{F_{net}}{m} \). Mass \( m = 8 \, \text{kg} \), so \( a = \frac{22}{8} = 2.75 \, \text{m/s}^2 \).

Answer:

B. 2.75 m/s²