QUESTION IMAGE
Question
question
solve for $x$. leave your answer in
simplest radical form.
answer
attempt 1 out of 2
$x = $
Step1: Find the height of the large right - triangle
Use the Pythagorean theorem \(a^{2}+b^{2}=c^{2}\). Let the height be \(h\). For the large right - triangle with hypotenuse \(c = 10\) and base \(a = 9\), we have \(h=\sqrt{10^{2}-9^{2}}\).
$$h=\sqrt{100 - 81}=\sqrt{19}$$
Step2: Use the Pythagorean theorem for the small right - triangle
For the small right - triangle with one leg \(h=\sqrt{19}\) and the other leg \(4\), and hypotenuse \(x\). By the Pythagorean theorem \(x=\sqrt{(\sqrt{19})^{2}+4^{2}}\).
$$x=\sqrt{19 + 16}=\sqrt{35}$$
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\(x=\sqrt{35}\)