Question

question
select the correct answer.
what does the \g\ in newtons law of universal gravitation represent?
acceleration due to gravity
gravitational constant
gravitational pull of the sun
deceleration due to gravity

Explanation:

Newton's law of universal gravitation is \( F = G\frac{m_1m_2}{r^2} \), where \( F \) is the gravitational force between two objects, \( m_1 \) and \( m_2 \) are the masses of the two objects, \( r \) is the distance between their centers of mass. In this formula, \( G \) is a constant value that is the same throughout the universe (for non - relativistic cases). The acceleration due to gravity \( g\) (on Earth's surface \( g=\frac{GM}{R^{2}}\), where \( M\) is Earth's mass and \( R\) is Earth's radius) is not the same as \( G\). The gravitational pull of the Sun is a force \( F = G\frac{M_{\text{Sun}}m}{r^{2}}\) (where \( m\) is the mass of an object in the Sun's gravitational field). Deceleration due to gravity is not what \( G\) represents. \( G\) is the gravitational constant which has a value of approximately \( 6.67\times 10^{- 11}\space N\cdot m^{2}/kg^{2}\).

Answer:

gravitational constant