Question

question 4 0.5 pts which of these crosses will only produce heterozygous offspring? aa × aa aa × aa aa × aa aa × aa

Explanation:

Step1: Analyze \(AA\times Aa\)

Parents: \(AA\) (gametes \(A\)) and \(Aa\) (gametes \(A\) and \(a\)). Offspring genotypes: \(AA\) (\(A\times A\)) and \(Aa\) (\(A\times a\)). So, there are homozygous (\(AA\)) and heterozygous (\(Aa\)) offspring.

Step2: Analyze \(AA\times aa\)

Parents: \(AA\) (gametes \(A\)) and \(aa\) (gametes \(a\)). Offspring genotype: \(Aa\) (\(A\times a\)) for all offspring.

Step3: Analyze \(Aa\times Aa\)

Parents: \(Aa\) (gametes \(A\) and \(a\)). Offspring genotypes: \(AA\) (\(A\times A\)), \(Aa\) (\(A\times a\) and \(a\times A\)), \(aa\) (\(a\times a\)). So, there are homozygous (\(AA\) and \(aa\)) and heterozygous (\(Aa\)) offspring.

Step4: Analyze \(Aa\times aa\)

Parents: \(Aa\) (gametes \(A\) and \(a\)) and \(aa\) (gametes \(a\)). Offspring genotypes: \(Aa\) (\(A\times a\)) and \(aa\) (\(a\times a\)). So, there are heterozygous (\(Aa\)) and homozygous (\(aa\)) offspring.

Answer:

\(AA\times aa\)