Question

question 6 (1 point)
a block of wood has a mass of 1.25 kg. how much force does it exert on the ground?
the normal force is mass (kg) multiplied by the acceleration due to gravity (g), where g
= 9.8 m/s²
o a 12.25 n
o b 12n
o c 1.25n
o d 9.8m/s

question 7 (1 point)
aside from the skid steering, friction in a robot is much more complicated and difficult to account for. at the wheels, static friction cannot
be overcome, or else the robot will spin out. furthermore, static and kinetic friction are internal to the drive train and these are very
difficult to quantify in terms of normal forces and coefficients of friction. often this type of friction can only be found indirectly
o true
o false

Explanation:

Step1: Calculate the force

The formula for force \(F = mg\), where \(m = 1.25\space kg\) and \(g=9.8\space m/s^{2}\).

$$F=1.25\times9.8$$

Step2: Solve the multiplication

$$1.25\times9.8=(1 + 0.25)\times9.8=9.8+0.25\times9.8=9.8 + 2.45=12.25\space N$$

Answer:

A. 12.25N