QUESTION IMAGE
Question
question 4 (1 point) (a) ? =
Step1: Recall angle - sum property of a triangle
The sum of interior angles of a triangle is 180°. Let the third - interior angle of the triangle be $x$. Then $x + 41^{\circ}+61^{\circ}=180^{\circ}$.
Step2: Solve for the third - interior angle
$x=180^{\circ}-(41^{\circ} + 61^{\circ})=180^{\circ}-102^{\circ}=78^{\circ}$.
Step3: Use the linear - pair property
The unknown exterior angle and the third - interior angle $x$ form a linear pair. A linear pair of angles sums to 180°. Let the exterior angle be $y$. Then $y + x=180^{\circ}$. Since $x = 78^{\circ}$, $y=180^{\circ}-78^{\circ}=102^{\circ}$.
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$102^{\circ}$