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question
multiply.
$x(-10x^2 - 8)$
Step1: Apply distributive property
Using the distributive property \(a(b + c)=ab+ac\), here \(a = x\), \(b=- 10x^{2}\), \(c = - 8\). So we have \(x\times(-10x^{2})+x\times(-8)\).
Step2: Simplify each term
For the first term \(x\times(-10x^{2})\), using the rule of exponents \(a^{m}\times a^{n}=a^{m + n}\), we get \(-10x^{1 + 2}=-10x^{3}\). For the second term \(x\times(-8)=-8x\). Combining these two terms, we have \(-10x^{3}-8x\).
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\(-10x^{3}-8x\)