Question

question 5 (multiple choice worth 5 points)
(applications of systems mc)
brad and beverly have played 46 matches of chess. brad has won 9 times more than beverly. if x is the number of times brad has won and y is the number of times beverly has won, which system of equations representing the situation?
\\(\bigcirc x + y = 9\\)\\(x = y + 46\\)\\(\bigcirc x + y = 46\\)\\(y = x + 9\\)\\(\bigcirc x + y = 46\\)\\(x = y + 9\\)\\(\bigcirc x + y = 9\\)\\(y = x + 46\\)

Explanation:

Step1: Analyze total matches

The total number of chess matches played is 46, so the sum of Brad's wins (\(x\)) and Beverly's wins (\(y\)) should be 46. Thus, \(x + y = 46\).

Step2: Analyze the win difference

Brad has won 9 times more than Beverly, so \(x = y + 9\).

Answer:

The system of equations \(x + y = 46\) and \(x = y + 9\) (the third option in the list, assuming the third option is \(x + y = 46\) and \(x = y + 9\))