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Question
question 5 (multiple choice worth 4 points) (01 07r mc) ray at bisects ∠mar. if m∠mat=(8x - 3)° and m∠rat=(2x + 9)°, what is m∠mar? 26° 13° 8° 2° question 6 (multiple choice worth 4 points) (01 06r mc)
Step1: Set up equation based on angle - bisector property
Since ray AT bisects ∠MAR, then m∠MAT = m∠RAT. So, 8x - 3=2x + 9.
Step2: Solve for x
Subtract 2x from both sides: 8x-2x - 3=2x-2x + 9, which simplifies to 6x - 3=9. Then add 3 to both sides: 6x-3 + 3=9 + 3, giving 6x=12. Divide both sides by 6: x = 2.
Step3: Find m∠MAT or m∠RAT
Substitute x = 2 into m∠MAT = 8x - 3. So, m∠MAT=8×2 - 3=16 - 3 = 13°.
Step4: Calculate m∠MAR
Since m∠MAR=m∠MAT + m∠RAT and m∠MAT = m∠RAT, m∠MAR = 2×m∠MAT. So, m∠MAR=2×13° = 26°.
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26°