Question

question 1
a metal block with a mass of 55.0 g. was heated from 16.4 c to 46.4 c. the specific heat of the metal is 0.978 j/gc. how many joules of energy was absorbed by this metal block?

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_{final}-T_{initial}=46.4 - 16.4=30.0\ ^{\circ}C$

Step2: Use the heat - absorption formula

The formula for heat absorption is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the temperature change.
Given $m = 55.0\ g$, $c=0.978\ J/g^{\circ}C$, and $\Delta T = 30.0\ ^{\circ}C$
$Q=(55.0\ g)\times(0.978\ J/g^{\circ}C)\times(30.0\ ^{\circ}C)$
$Q = 55.0\times0.978\times30.0$
$Q=55.0\times29.34$
$Q = 1613.7\ J$

Answer:

$1613.7$