Question

question 2: mechanical comprehension what is the force f needed to balance this lever? a: 20 kg b: 22 kg c: 25 kg d: 30 kg

Explanation:

Step1: Calculate the total torque on the left - hand side

Torque is calculated as \(Torque = Force\times Distance\).
The torque due to the \(10 - kg\) weight: \(T_1=10\times(2 + 3)=10\times5 = 50\) (using the distance from the fulcrum).
The torque due to the \(20 - kg\) weight: \(T_2=20\times3=60\).
The total torque on the left - hand side \(T_{left}=T_1 + T_2=50+60 = 110\).

Step2: Calculate the force \(F\) using the torque balance equation

For the lever to be in balance, \(T_{left}=T_{right}\).
The torque on the right - hand side \(T_{right}=F\times5\) (where the distance from the fulcrum is \(5\) ft).
Since \(T_{left}=T_{right}\), we have \(110=F\times5\).
Solving for \(F\), we get \(F=\frac{110}{5}=22\).

Answer:

B. \(22\space kg\)