Question

question
if mars travels at 24,126 meters per second in orbit around the sun and takes 1.88 earth years to complete its orbit, what is
the total distance in miles mars travels throughout its complete orbit? (round your answer to the nearest whole number
and do not include units or commas in your answer.) note: there are 1,609 meters in a mile. use 365 for the number of
days in an earth year.
sorry, thats incorrect. try again?
889096073
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Explanation:

Step1: Convert time to seconds

First, convert \(1.88\) Earth - years to seconds.
Number of days in \(1.88\) years: \(1.88\times365\) days.
Number of hours in \(1.88\times365\) days: \(1.88\times365\times24\) hours.
Number of minutes in \(1.88\times365\times24\) hours: \(1.88\times365\times24\times60\) minutes.
Number of seconds in \(1.88\times365\times24\times60\) minutes: \(t = 1.88\times365\times24\times60\times60\) seconds.

$$t=1.88\times365\times24\times3600=1.88\times365\times86400 = 1.88\times31536000=59287680$$

seconds.

Step2: Calculate the distance in meters

Use the formula \(d = v\times t\), where \(v = 24126\) m/s and \(t = 59287680\) s.
\(d_m=24126\times59287680\)

$$d_m = 24126\times59287680=(2.4126\times10^{4})\times(5.928768\times10^{7})=2.4126\times5.928768\times10^{11}\approx1.4303\times10^{12}\text{ meters}$$

Step3: Convert meters to miles

Since \(1\) mile \( = 1609\) meters, then \(d_{mi}=\frac{d_m}{1609}\)

$$d_{mi}=\frac{24126\times59287680}{1609}=\frac{1.4303\times 10^{12}}{1.609\times10^{3}}=\frac{1.4303}{1.609}\times10^{9}\approx0.889\times10^{9}=889000000$$

Answer:

\(889000000\)