Question

question 8
a marble rolling 8.3 m/s rolls off a table that is 2 meters high. how far from the
edge of the table does it land?

Explanation:

Step1: Calculate the time it takes for the marble to fall vertically

Use the equation \( h=\frac{1}{2}gt^{2} \) (where \( h = 2m \), \( g = 9.8m/s^{2} \)).

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Step2: Calculate the horizontal distance

The horizontal velocity \( v_{x}=8.3m/s \), and the horizontal distance \( x = v_{x}t \).

$$ x=8.3\times0.64 = 5.312m $$

Answer:

\( 5.312m \)