Question

question in △lmn, the measure of ∠n = 90°, ml = 53, ln = 45, and nm = 28. what ratio represents the sine of ∠l? answer attempt 1 out of 2

Explanation:

Step1: Recall sine - definition

In a right - triangle, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. For $\angle L$ in right - triangle $\triangle LMN$ with $\angle N = 90^{\circ}$, the side opposite $\angle L$ is $NM$ and the hypotenuse is $ML$.

Step2: Calculate sine of $\angle L$

$\sin L=\frac{NM}{ML}$. Given $ML = 53$ and $NM=28$, so $\sin L=\frac{28}{53}$.

Answer:

$\frac{28}{53}$