Question

question given the points f(-7,1) and e(-2,-7), determine the position vector of $overrightarrow{ef}$. select the correct answer below: (-8,5) (-5,-8) (8,5) (-5,8) (5,-8) (8,-5)

Explanation:

Step1: Recall vector formula

If we have two points $E(x_1,y_1)$ and $F(x_2,y_2)$, the vector $\overrightarrow{EF}=\langle x_2 - x_1,y_2 - y_1
angle$.
Here $x_1=-2,y_1 = - 7,x_2=-7,y_2 = 1$.

Step2: Calculate x - component

$x_2 - x_1=-7-(-2)=-7 + 2=-5$.

Step3: Calculate y - component

$y_2 - y_1=1-(-7)=1 + 7 = 8$.
So $\overrightarrow{EF}=\langle - 5,8
angle$.

Answer:

B. $\langle - 5,8
angle$