Question

question 2
a force, f, acts on a spring with a spring constant k = 250 n/m. if the spring compresses 15 cm, what force (in newtons) acted on the spring?
a 37.5 n
b 16.7 n
c 3.75 n
d 3750 n

Explanation:

Step1: Convert the unit of compression

The compression \(x = 15\ cm=0.15\ m\) (since \(1\ m = 100\ cm\)).

Step2: Apply Hooke's Law

Hooke's Law is \(F = kx\), where \(k = 250\ N/m\) and \(x = 0.15\ m\).
Substitute the values: \(F=250\times0.15\).
Calculate \(250\times0.15=(25\times10)\times\frac{15}{100}=25\times\frac{15}{10}=\frac{375}{10}=37.5\ N\).

Answer:

A. \(37.5\ N\)