Question

question
find the volume of a pyramid with a square base, where the side length of the base is 10 m and the height of the pyramid is 7.2 m. round your answer to the nearest tenth of a cubic meter.
answer attempt 1 out of 2
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Explanation:

Step1: Recall the volume formula for a pyramid

The volume \( V \) of a pyramid is given by the formula \( V=\frac{1}{3}Bh \), where \( B \) is the area of the base and \( h \) is the height of the pyramid. For a square base with side length \( s \), the area of the base \( B = s^{2}\).

Step2: Calculate the area of the square base

Given the side length of the base \( s = 10\space m \), so the area of the base \( B=s^{2}=10^{2}=100\space m^{2} \).

Step3: Substitute the values into the volume formula

We know \( B = 100\space m^{2} \) and \( h = 7.2\space m \). Substituting these into the volume formula \( V=\frac{1}{3}Bh \), we get \( V=\frac{1}{3}\times100\times7.2 \).

Step4: Perform the calculation

First, calculate \( 100\times7.2 = 720 \). Then, \( \frac{1}{3}\times720=240 \). But wait, we need to round to the nearest tenth? Wait, no, 240 is already a whole number. Wait, let's check the calculation again. Wait, \( \frac{1}{3}\times100\times7.2=\frac{720}{3} = 240.0 \) when rounded to the nearest tenth.

Answer:

\( 240.0 \)