Question

question
find the surface area of a square pyramid with side length 4 cm and slant height 4 cm.
answer attempt 1 out of 2

Explanation:

Step1: Calculate the base area

The base is a square with side length \(s = 4\) cm. The area of the base \(B\) is \(B=s^{2}\).
\(B = 4^{2}=16\) \(cm^{2}\)

Step2: Calculate the lateral surface area

The lateral surface area of a square - pyramid is \(LSA = 2sl\), where \(s\) is the side length of the base and \(l\) is the slant height. Here, \(s = 4\) cm and \(l = 4\) cm.
\(LSA=2\times4\times4 = 32\) \(cm^{2}\)

Step3: Calculate the total surface area

The total surface area \(SA\) of a square - pyramid is \(SA=B + LSA\).
\(SA=16 + 32\)
\(SA = 48\) \(cm^{2}\)

Answer:

\(48\)