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Question
question
factor completely.
$81x^2 - 49$
answer attempt 1 out of 2
Step1: Identify the form
The expression \(81x^2 - 49\) is a difference of squares, since \(81x^2=(9x)^2\) and \(49 = 7^2\). The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\).
Step2: Apply the formula
Let \(a = 9x\) and \(b = 7\). Then, substituting into the difference of squares formula, we get \((9x + 7)(9x - 7)\).
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\((9x + 7)(9x - 7)\)