Question

question
factor completely.
$36x^2 - 121$

Explanation:

Step1: Identify as difference of squares

The expression \(36x^2 - 121\) can be written as \((6x)^2 - 11^2\), which is a difference of squares \(a^2 - b^2\) where \(a = 6x\) and \(b = 11\).

Step2: Apply difference of squares formula

The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\). Substituting \(a = 6x\) and \(b = 11\), we get \((6x + 11)(6x - 11)\).

Answer:

\((6x + 11)(6x - 11)\)