Question

question 6
an experimental 1500 - kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. what is the kinetic energy of the car?
zero joules
1.6×10⁴j
3.6×10⁵j
3.3×10⁴j
7.2×10⁵j

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy is \(K = \frac{1}{2}mv^{2}\), where \(m\) is the mass of the object and \(v\) is its velocity.

Step2: Identify the values of \(m\) and \(v\)

Given that \(m = 1500\space kg\) and \(v=22\space m/s\).

Step3: Substitute the values into the formula

$$
LATEXBLOCK0
$$

Answer:

\(3.6\times 10^{5}\space J\) (the slight difference in the exponent's coefficient is due to rounding in the multiple - choice options)