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Question
question 2 of 5
choose all fractions equivalent to each given fraction.
given fraction check all fractions that are equivalent to the given fraction.
(a) $-\frac{3}{8}$ $\frac{-3}{8}$ $\frac{3}{8}$ $\frac{3}{-8}$ $\frac{-3}{-8}$
given fraction check all fractions that are equivalent to the given fraction.
(b) $\frac{-7}{-10}$ $-\frac{7}{10}$ $\frac{-7}{10}$ $\frac{7}{-10}$ $\frac{7}{10}$
Part (a)
Step 1: Recall the rule of signs for fractions
The rule is that \(\frac{-a}{b}=\frac{a}{-b}=-\frac{a}{b}\), where \(a,b\) are positive real numbers. For the given fraction \(-\frac{3}{8}\):
- For \(\frac{-3}{8}\): Using the rule \(-\frac{a}{b}=\frac{-a}{b}\) (here \(a = 3,b = 8\)), so \(-\frac{3}{8}=\frac{-3}{8}\).
- For \(\frac{3}{8}\): The sign is positive, while the given fraction is negative, so they are not equivalent.
- For \(\frac{3}{-8}\): Using the rule \(-\frac{a}{b}=\frac{a}{-b}\) (here \(a = 3,b = 8\)), so \(-\frac{3}{8}=\frac{3}{-8}\).
- For \(\frac{-3}{-8}\): The product of two negative signs is positive, so \(\frac{-3}{-8}=\frac{3}{8}\), which is not equal to \(-\frac{3}{8}\).
Step 2: Identify equivalent fractions
From the above analysis, the fractions equivalent to \(-\frac{3}{8}\) are \(\frac{-3}{8}\) and \(\frac{3}{-8}\).
Part (b)
Step 1: Simplify the given fraction
First, simplify \(\frac{-7}{-10}\). The rule for dividing two negative numbers is that \(\frac{-a}{-b}=\frac{a}{b}\) (where \(a,b>0\)). So \(\frac{-7}{-10}=\frac{7}{10}\). Now we check each option:
- For \(-\frac{7}{10}\): The sign is negative, while \(\frac{7}{10}\) is positive, so not equivalent.
- For \(\frac{-7}{10}\): The sign is negative, while \(\frac{7}{10}\) is positive, so not equivalent.
- For \(\frac{7}{-10}\): \(\frac{7}{-10}=-\frac{7}{10}\), which is not equal to \(\frac{7}{10}\), so not equivalent.
- For \(\frac{7}{10}\): We already found that \(\frac{-7}{-10}=\frac{7}{10}\), so this is equivalent.
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(a) The equivalent fractions are \(\boldsymbol{\frac{-3}{8}}\) and \(\boldsymbol{\frac{3}{-8}}\)
(b) The equivalent fraction is \(\boldsymbol{\frac{7}{10}}\)