Question

question
a chocolatier makes chocolate bon - bons in the shape of a sphere with a radius of 0.9 cm. the chocolate used in the bon - bons has a density of 1.34 g/cm³. if the chocolate used costs $0.06 per gram, how much would the chocolate for 190 bon - bons cost, to the nearest cent?
answer attempt 1 out of 2

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Explanation:

Step1: Calculate volume of one bon - bon

The formula for the volume of a sphere is $V=\frac{4}{3}\pi r^{3}$. Given that the radius $r = 0.9\space cm$.
Substitute $r = 0.9$ into the formula:
$V=\frac{4}{3}\pi(0.9)^{3}=\frac{4}{3}\pi\times0.729\approx\frac{4}{3}\times3.1416\times0.729\approx3.0536\space cm^{3}$

Step2: Calculate mass of one bon - bon

Density formula is $
ho=\frac{m}{V}$, so $m=
ho V$. Given $
ho = 1.34\space g/cm^{3}$ and $V\approx3.0536\space cm^{3}$.
$m = 1.34\times3.0536\approx4.0918\space g$

Step3: Calculate cost of one bon - bon

The cost per gram is $\$0.06$. So cost of one bon - bon $C_{1}=0.06\times4.0918\approx\$0.2455$

Step4: Calculate cost of 190 bon - bons

Cost of 190 bon - bons $C = 190\times0.2455\approx46.645$
Rounding to the nearest cent, we get $C\approx\$46.65$

Answer:

$\$46.65$