Question

question #5
calculate the energy of a photon of visible light with a wavelength of 432 nm.
j
calculate the energy of one mole of photons of visible light with a wavelength of 432 nm. (note: this is the same wavelength as in the previous question).
kj/mol

Explanation:

Step1: Convert wavelength to meters

Given \(\lambda = 432\ nm=432\times10^{-9}\ m\)

Step2: Use the formula \(E = hc/\lambda\)

where \(h = 6.626\times 10^{-34}\ J\cdot s\) (Planck's constant) and \(c = 3\times 10^{8}\ m/s\) (speed of light)

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Step3: Calculate energy for one - mole of photons

Use \(N_{A}=6.022\times 10^{23}\ mol^{-1}\) (Avogadro's number)
\(E_{mol}=N_{A}\times E\)

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Answer:

\(4.60\times 10^{-19}\ J\)
\(277\ kJ/mol\)