Question

question 34 (1 point) page 34 using the appropriate special triangle, determine θ if 0° ≤ θ ≤ 90° for cosθ = √3/2. a) 30° b) 45° c) 90° d) 60°

Explanation:

Step1: Recall cosine values of special angles

We know that for special angles in the range \(0^{\circ}\leq\theta\leq90^{\circ}\), \(\cos30^{\circ}=\frac{\sqrt{3}}{2}\), \(\cos45^{\circ}=\frac{\sqrt{2}}{2}\), \(\cos60^{\circ}=\frac{1}{2}\), and \(\cos90^{\circ} = 0\).

Answer:

A. \(30^{\circ}\)