Question

question 23 (5 points)
in the given figure, find \\( \angle p q s \\), if \\( \angle p q r=5 x+25 \\) and \\( \angle s q r=2 x+10 \\).

Explanation:

Step1: Use the angle - addition postulate

We know that \(\angle PQR=\angle PQS+\angle SQR\). Given \(\angle PQR = 5x + 25\) and \(\angle SQR=2x + 10\). Let \(\angle PQS=y\). Then \(5x + 25=y+(2x + 10)\).

Step2: Solve for \(y\)

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Answer:

\(3(x + 5)\)