Question

question 22 (1 point) what is the minimum value for the function f(x)=4.5x^2 - 7.1x + 3.9? round to two decimal places. a) 6.70 b) 1.10 c) 3.90 d) 0.79

Explanation:

Step1: Find the derivative

For the function $y = 4.5x^{2}-7.1x + 3$, the derivative $y^\prime=9x - 7.1$

Step2: Set the derivative equal to 0

Set $y^\prime = 0$, so $9x-7.1 = 0$. Solving for $x$ gives $x=\frac{7.1}{9}\approx0.79$

Step3: Substitute $x$ into the original function

Substitute $x = \frac{7.1}{9}$ into $y = 4.5x^{2}-7.1x + 3$.

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Answer:

d) 0.79