Question

question 17
1 pts
find the orbital period (in years) of an asteroid whose average distance from the sun is 5 au. use keplers 3rd law and only enter the number, not the units 2 pt question

Explanation:

Step1: Recall Kepler's 3rd law

$T^{2}=a^{3}$, where $T$ is the orbital period in years and $a$ is the average distance from the sun in astronomical - units (AU).

Step2: Substitute the given value of $a$

Given $a = 5$ AU. Substitute $a$ into the formula: $T^{2}=5^{3}=125$.

Step3: Solve for $T$

$T=\sqrt{125}\approx11.18$.

Answer:

$11.18$