Question

question 14
3 pts
if a galaxy is located at a distance of 18 mpc, and it is found to have recessional velocity of 1170 km/sec, what is hubbles constant based only on this galaxy? 3 pts, recall v = h x d with v = velocity in km/sec and d = distance in mega - parsecs, mpc

Explanation:

Step1: Rearrange Hubble's law for H

$H = \frac{v}{d}$

Step2: Substitute values (v=1170 km/s, d=18 Mpc)

$H = \frac{1170}{18}$

Step3: Calculate H

$H = 65$

Answer:

65 km/s/Mpc