Question

question 11
if galaxy a is four times more distant than galaxy b, then according to hubbles
law, galaxy a will recede ____________ times faster than galaxy b.

Explanation:

Step1: State Hubble's Law

Hubble's Law is $v = H_0 d$, where $v$ = recession velocity, $H_0$ = Hubble constant, $d$ = distance.

Step2: Define distances of galaxies

Let $d_B = d$, so $d_A = 4d$.

Step3: Calculate velocities

$v_B = H_0 d$, $v_A = H_0 (4d) = 4H_0 d$.

Step4: Find velocity ratio

$\frac{v_A}{v_B} = \frac{4H_0 d}{H_0 d} = 4$.

Answer:

4