Question

question 1 of 10 which of the following are solutions to the equation below? check all that apply. $x^{2}+5x - 8=4x + 4$ a. -2 b. 4 c. 3 d. 5 e. -4 f. -3

Explanation:

Step1: Rearrange to standard quadratic form

First, move all terms to one - side of the equation: $x^{2}+5x - 8-(4x + 4)=0$, which simplifies to $x^{2}+5x-8 - 4x - 4 = 0$, and further to $x^{2}+x - 12=0$.

Step2: Factor the quadratic equation

The quadratic equation $x^{2}+x - 12 = 0$ can be factored as $(x + 4)(x - 3)=0$.

Step3: Solve for x

Using the zero - product property, if $(x + 4)(x - 3)=0$, then $x+4 = 0$ or $x - 3=0$. Solving $x+4 = 0$ gives $x=-4$, and solving $x - 3=0$ gives $x = 3$.

Answer:

C. 3, E. -4