Question

question 8 of 10

the vertex of this parabola is at (-4, -1). when the \\(y\\)-value is 0, the \\(x\\)-value is 2. what is the coefficient of the squared term in the parabolas equation?

a. 3
b. -3
c. -6
d. 6

Explanation:

Set up the horizontal parabola equation using the vertex

$$ x = a(y - k)^2 + h $$

$$ (h, k) = (-4, -1) \implies x = a(y + 1)^2 - 4 $$

Substitute the given point to solve for the coefficient

$$ (x, y) = (2, 0) $$

$$ 2 = a(0 + 1)^2 - 4 $$

$$ 2 = a(1) - 4 \implies a = 6 $$

Answer:

• A. 3
• B. -3
• C. -6
• D. 6 (Correct answer)