Question

question 6 of 10 a student redid the experiment of mixing room - temperature water and warm water. this time, she used half the original amount of warm water. how will the final temperature be different? a. it will be higher, because all parts of the mixture will end up at the same temperature. b. it will be lower, because the amount of water in the mixture will be less. c. it will be the same, because all parts of the mixture will end up at the same temperature d. it will be lower, because less thermal energy is transferred to the room - temperature water.

Explanation:

Step1: Consider heat - transfer principle

When mixing warm and room - temperature water, the final temperature is determined by the heat transfer between them. The heat $Q = mc\Delta T$, where $m$ is mass, $c$ is specific heat capacity (constant for water), and $\Delta T$ is temperature change. If the amount of warm water is halved, the total thermal energy available to raise the temperature of the mixture is less.

Step2: Analyze impact on final temperature

Since there is less thermal energy from the warm water to heat up the combined water (room - temperature and warm water), the final temperature of the mixture will be lower.

Answer:

D. It will be lower, because less thermal energy is transferred to the room - temperature water.