Question

question 10
1 pts
a heterozygous tall pea plant is crossed with a short plant. the probability that an f₁ plant will be tall is
there is no way to tell
50%.
75%.
25%.
100%.

Explanation:

Step1: Determine the genotypes

Let \( T \) represent the allele for tall (dominant) and \( t \) represent the allele for short (recessive). A heterozygous tall pea plant has the genotype \( Tt \), and a short plant has the genotype \( tt \).

Step2: Set up the Punnett square

Gametes of \( Tt \)	Gametes of \( tt \)
\( t \)	\( t \)

The possible genotypes of the \( F_1 \) generation are \( Tt \) (tall) and \( tt \) (short).

Step3: Calculate the probability

Out of the two possible genotypes (\( Tt \) and \( tt \)), one is \( Tt \) (tall). So the probability \( P=\frac{1}{2}= 50\%\)

Answer:

50%