Question

question 10 (1 point)
during batting practice, a 0.30 kg baseball is hit with a bat. the ball left the bat at 80 m/s. if the incoming pitch was traveling at -60 m/s, what was the change in momentum of the ball?
o a 140 kg.m/s
b -140 kg.m/s
o c 42 kg.m/s
d -42 kg.m/s

Explanation:

Step1: Recall the formula for change in momentum

The formula for change in momentum \(\Delta p = p_{final}-p_{initial}\), and momentum \(p = mv\).

Step2: Identify the values of mass, final velocity and initial velocity

Given \(m = 0.30\space kg\), \(v_{final}=80\space m/s\), \(v_{initial}=- 60\space m/s\)

Step3: Calculate the final and initial momentum

\(p_{final}=mv_{final}=0.30\times80 = 24\space kg\cdot m/s\)
\(p_{initial}=mv_{initial}=0.30\times(-60)=- 18\space kg\cdot m/s\)

Step4: Calculate the change in momentum

\(\Delta p=p_{final}-p_{initial}=24-(-18)\)
\(\Delta p = 24 + 18=42\space kg\cdot m/s\)

Answer:

C. \(42\space kg\cdot m/s\)