Question

question 10 (fill - in - the - blank worth 4 points)
(06.03 mc)
a large emerald with a mass of 378.24 grams was recently discovered in a mine. if the density of the emerald is 2.76\frac{grams}{cm^{3}}, what is the volume? round to the nearest hundredth when necessary and only enter numerical values, which
can include a decimal point.
answer for blank 1:

Explanation:

Step1: Recall the density formula

Density formula is \(
ho=\frac{m}{V}\), where \(
ho\) is density, \( m\) is mass, and \( V\) is volume. We need to solve for \( V\), so \( V = \frac{m}{
ho}\).

Step2: Substitute the given values

Given \( m = 378.24\) grams and \(
ho=2.76\frac{grams}{cm^{3}}\). Then \( V=\frac{378.24}{2.76}\).

Step3: Calculate the value

\( \frac{378.24}{2.76}=137.043478\approx137.04\) (rounded to the nearest hundredth).

Answer:

137.04