Question

question 2 of 10
according to this diagram, what is sin 28°?

a. 15/8
b. 8/17
c. 17/8
d. 15/17
e. 17/15
f. 8/15

Explanation:

Step1: Recall sine definition

In a right triangle, $\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify sides for $28^\circ$

For $\theta = 28^\circ$, opposite side is $8$, hypotenuse is $17$.

Step3: Calculate $\sin 28^\circ$

$\sin 28^\circ = \frac{8}{17}$. Wait, no, wait—wait, the options: option B is $\frac{8}{17}$? Wait, let me check again. Wait, the angle $28^\circ$: opposite side is the side opposite to $28^\circ$, which is $8$, hypotenuse is $17$. So $\sin 28^\circ = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{8}{17}$, which is option B. Wait, but let me confirm the triangle: right triangle, angles $28^\circ$, $62^\circ$, $90^\circ$. Sides: opposite $28^\circ$ is $8$, adjacent is $15$, hypotenuse $17$. So sine of $28^\circ$ is opposite over hypotenuse, so $\frac{8}{17}$, which is option B.

Answer:

B. $\frac{8}{17}$