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question 8 of 10
a 10 - foot ladder is leaning against a building. the ladder makes a 45 - degree angle with the building. how far up the building does the ladder reach?
a. 5\sqrt{2} feet
b. 10\sqrt{2} feet
c. 20\sqrt{2} feet
d. 5 feet
Step1: Identify right triangle components
Hypotenuse (ladder) = 10 ft, angle with building = 45°, height (h) = adjacent side.
Step2: Apply cosine function
$\cos(45^\circ) = \frac{h}{10}$
Step3: Solve for h
$h = 10 \cdot \cos(45^\circ) = 10 \cdot \frac{\sqrt{2}}{2} = 5\sqrt{2}$
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A. 5√2 feet